7(^3-2x)=5^4x

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Solution for 7(^3-2x)=5^4x equation: 



7(^3-2x)=5^4x

We move all terms to the left:

7(^3-2x)-(5^4x)=0

We multiply parentheses

-14x-5^4x+=0

We add all the numbers together, and all the variables

-14x-5^4x=0

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